The equivalent conductance of `1 M` benzoic acid is `12.8 ohm^(-1) cm^(2)`. If the conductance of benzoate ion and `H^(+)` ion are `12` and `288.42 ohm^(-1) cm^(2)` respectively. Its degree of dissociation is :A. `39 %`B. `3.9 %`C. `0.35 %`D. `0.039 %`

The equivalent conductance of `1 M` benzoic acid is `12.8 ohm^(-1) cm^

1.	The equivalent conductance of `1 M` benzoic acid is `12.8 ohm^(-1) cm^(2)`. If the conductance of benzoate ion and `H^(+)` ion are `12` and `288.42 ohm^(-1) cm^(2)` respectively. Its degree of dissociation is :A. `39 %`B. `3.9 %`C. `0.35 %`D. `0.039 %`
Answer» Correct Answer - B `overset(@)(Lambda)(C_(6)H_(5)COOH) = overset(@)(Lambda)(C_(6)H_(5)COO^(-)) + overset(@)(Lambda)_((H^(+)))` `= 42 xx 288.42 = 330.42` `alpha = (Lambda_(m)^(C))/(overset(@)(Lambda)_(m)) = (12.8)/(330.42) = 0.0387 = 3.87%`

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The equivalent conductance of `1 M` benzoic acid is `12.8 ohm^(-1) cm^(2)`. If the conductance of benzoate ion and `H^(+)` ion are `12` and `288.42 ohm^(-1) cm^(2)` respectively. Its degree of dissociation is :A. `39 %`B. `3.9 %`C. `0.35 %`D. `0.039 %`

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