The equilibrium constant Kc of the reaction, A2(g)+B2(g)⇌2AB(g) at 1 – InterviewSolution

1.	The equilibrium constant Kc of the reaction, A2(g)+B2(g)⇌2AB(g) at 100∘C is 64. If a one litre flask containing one mole of A2 is connected to a two litre flask containing one mole of B2, how many moles of AB will be formed at 373 K?
Answer» The equilibrium constant $K_{c}$ of the reaction, $A_{2} (g) + B_{2} (g) ⇌ 2 A B (g)$ at $100^{\circ} C$ is $64$ . If a one litre flask containing one mole of $A_{2}$ is connected to a two litre flask containing one mole of $B_{2},$ how many moles of $A B$ will be formed at $373 K$ ?

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