The equilibrium constant for the reaction is H2+Br2→2HBr at 1024 k – InterviewSolution

1.	The equilibrium constant for the reaction is H2+Br2→2HBr at 1024 k is 1.60×105. Find the equilibrium pressure of all gases if 10 bar of HBr is introduced into a sealed container at 1024 K.
Answer» The equilibrium constant for the reaction is $H_{2} + B r_{2} \to 2 H B r$ at 1024 k is $1.60 \times 10^{5} .$ Find the equilibrium pressure of all gases if $10 b a r$ of HBr is introduced into a sealed container at $1024 K$ .

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