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The equilibrium constant for the reaction is 10. Calculate the value of ∆ G° at 27°C

Answer»

if this is your QUESTION thenThe equilibrium constant for a reaction is 10. What will be the value of ΔG0 ? values(we know) R = 8.314 JK–1 mol–1, T = 300 K.From the expression, ΔG0 = -2.303 RT LOG KeqΔG0 for the reaction,= (2.303) (8.314 JK-1mol-1) (300 K) log10= -5744.14 Jmol-1= -5.744 kJ mol-1Explanation:hope this HELPS



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