1.

The equilibrium constant for the reaction is 10. Calculate the value of ∆G ; Given R = 8 J K-1 mol-1 ; T = 300 K.

Answer»

 ∆Gθ = -2.303 RT log K

Here, R = 8.0 JK-1 mol-1 ; T = 300K ; K = 10

 ∆Gθ  = -2.303 x 8 JK-1 mol-1 x 300 K x log10

         = -5527 J mol-1

          = -5.527 kJ mol-1



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