The equilibrium constant for the reaction given below is 2.0×10−7 a – InterviewSolution

1.	The equilibrium constant for the reaction given below is 2.0×10−7 at 300 K. Calculate the standard free energy change for the reaction. PCl5(g)⇌PCl3(g)+Cl2(g) Also, calculate the standard entropy change if, ΔH∘=28.40 kJ mol−1
Answer» The equilibrium constant for the reaction given below is $2.0 \times 10^{- 7}$ at 300 K. Calculate the standard free energy change for the reaction. $P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)$ Also, calculate the standard entropy change if, $Δ H^{\circ} = 28.40 k J m o l^{- 1}$

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