The equilibrium constant for a reaction is 10. What will be the value

1.	The equilibrium constant for a reaction is 10. What will be the value of ΔG°? R = 8.314 JK-1 mol-1, T = 300 K
Answer» ΔG° = -2.303 RT log Kc = -2.303 x (8.314 mol^-1 K^-1) x 300 K log 10 = -2.303 x 8.314 x 300 x 1 = -5527 J mol^-1 = -5.527 kJ mol^-1

The equilibrium constant for a reaction is 10. What will be the value of ΔG°? R = 8.314 JK-1 mol-1, T = 300 K

Answer»

ΔG° = -2.303 RT log Kc

= -2.303 x (8.314 mol^-1 K^-1) x 300 K log 10

= -2.303 x 8.314 x 300 x 1

= -5527 J mol^-1

= -5.527 kJ mol^-1

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The equilibrium constant for a reaction is 10. What will be the value of ΔG°? R = 8.314 JK-1 mol-1, T = 300 K

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