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The equilibrium `2Cu^(I) hArr Cu^(0) + Cu^(II)` in aqueous medium at `25^(@)C` shifts towards the left in the presence ofA. ` NO^(-)`B. `Cl^(-)`C. `SCN^(-)`D. `CN^(-)` |
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Answer» Correct Answer - B::C::D Cu (I) forms insouble compounds CuCl, CuCN and CuSCN. Hence , in the presence of `C1^(-) , CN^(-) and SCN^(-)` , the equilibrium shifts in the back direction . In fact, `Cu^(2+) " ions combine with " CH^(-) and SCN^(-)` to form compunds which are not stable and disociate to form `Cu^(+)` compounds/ complexes ` Cu^(2+) + 2 CN^(-) to Cu(CN)^(2)` ltbr ` Cu(CN)_(2) to 2 CuCN + (CN)_(2)` ` CuCN + 3 CN^(-) to [Cu (CN)_(4)]^(3-)` ` Cu^(2) + 4 SCN^(-) to [Cu(SCN)_(4) ]^(2-)` Similarly , `Cu^(2+) ` also combines with `Cl^(-)` ions to form `CuCl_(2)` which reacts with Cu to form CuCl, therby , shifting the equilibrium in the backward direction `CuCl_(2) + Cu to 2 CuCl` |
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