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The equilibirum constant `K_(c)` of the reaction, `2AhArrB+C "is" 0.5 "at" 25^(@)C and 1` atm. The raction will proceed in the backward direction when concentrations [A], [B] and [C] are respectively-A. `10^(-3),10^(-2) and 10^(-2) M`B. `10^(-1),10^(-2) and 10^(-2) M`C. `10^(-2),10^(-2) and 10^(-3) M`D. `10^(-2),10^(-3) and 10^(-3) M` |
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Answer» Correct Answer - A `Q=([B][C])/([A^(2)])&K_(C)=0.5` For option (A) `Q=((10^(-2))xx(10^(-2)))/([10^(-3)]^(2))=100` `& Qgt K_(C)` i.e., reaction proceed in backward direction |
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