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The equation `||x-2|+a|=4`can have four distinct real solutions for `x`if `a`belongs to the interval`(-oo,-4)`(b) `(-oo,0)``(4,oo)`(d) none of theseA. `(-oo, -4)`B. `(-oo,0]`C. `[4,oo)`D. none of these |
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Answer» Correct Answer - A `|x-2|+a=+-4` `or |x-2|= +-4-a` For four real roots, `4-a gt 0 and -4 -a gt 0` ` or a in (-oo, -4)` |
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