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The equation ofthe normal atP(x,y:) to thecirclex2 + y2 + 2gx + 2 fy+c=0is |
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Answer» Step-by-step EXPLANATION: (x^2+2gx)+(y^2+10fy)=c Now, COMPLETING the squares within the PARENTHESES, we GET (x^2+2gx+g^2)+ (y^2+10fy+(5f)^2)=c+g^2+(5f)^2 =(x+g)^2+(y+5f)^2=.......... |
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