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The equation of travelling wave is y = 60 cos (1800 t - 6x) , where y is in microns, t in seconds and x in metres. The ratio of maximum particle velocity to velocity of wave propagation is : |
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Answer» `3.6` COMPARING it with y = r cos `(omega t - kx)` r = `60 xx 10^(-6) m "" omega= 1800 s^(-1) k = 6 m^(-1) ` v = `(omega)/(K) = (1800)/(6)= 300 MS^(-1)`. now maximum particle velocity `V_(max).= r omega` = 60 `xx 10^(-6) xx 1800 = 108 xx 10^(-3)`. Now`(V_(max))/(v) = (108 xx 10^(-3))/(300) = 36 xx 10^(-5) = 3.6 xx 10^(-4)` correct CHOICE is (d). |
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