The equation of trajectory of a projectile thrown from a level groundnear the surface of earth is given by y = ax - bx^(2) , with y axis in vertical direction and x-axis in horizontal direction .a and b are constants. Then

The equation of trajectory of a projectile thrown from a level groundn

1.	The equation of trajectory of a projectile thrown from a level groundnear the surface of earth is given by y = ax - bx^(2) , with y axis in vertical direction and x-axis in horizontal direction .a and b are constants. Then
Answer» The range of the PROJECTILE is ` a/b` At ` x = a/(2b)` , the VELOCITY of projectile becomes zero The maximum height attained by projectile is ` a^(2)/(4b)` The angle of PROJECTION is ` tan^(-1)(a)` Answer :A::C::D

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The equation of trajectory of a projectile thrown from a level groundnear the surface of earth is given by y = ax - bx^(2) , with y axis in vertical direction and x-axis in horizontal direction .a and b are constants. Then

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