Saved Bookmarks
| 1. |
The equation of trajectory of a projectile is y=(x√3−gx220), where x and y are in meter. The maximum range of the projectile is (take g=10 m/s2) |
|
Answer» The equation of trajectory of a projectile is y=(x√3−gx220), where x and y are in meter. The maximum range of the projectile is (take g=10 m/s2) |
|