1.

The equation of the normal to the curve y=sin⁡x at the point (π,0) is :​

Answer»

Step-by-step explanation:

The normal LINE to a CURVE at a particular point is the line through that point and perpendicular to the tangent

Gradient of tangent when x=π

,dy/dx=cosx=cosπ=-1

So if the gradient of the tangent at the point (π,0) of the curve y = SINX is -1, the gradient of the normal is 1, since -1 × 1 = -1

The equation of the normal at the point (π,0) is therefore:

y - 0 =1 (x - π)

y=x-π

y-x+π=0


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