The equation of the line through (4,1), whose x-interceptis double its

1.	The equation of the line through (4,1), whose x-interceptis double its y-intercept, is(a) x+2y=6(b) 2x + y = 6(c) x+2y + 6 = 0 (d) none of these
Answer» Step-by-step explanation: The equation of the LINE through (4,1), whose x-intercept is double its y-intercept, is (a) x+2y=6 (B) 2X + y = 6 (C) x+2y + 6 = 0 (d) NONE of these

The equation of the line through (4,1), whose x-interceptis double its y-intercept, is(a) x+2y=6(b) 2x + y = 6(c) x+2y + 6 = 0 (d) none of these

Answer»

Step-by-step explanation:

The equation of the LINE through (4,1), whose x-intercept

is double its y-intercept, is

(a) x+2y=6

(B) 2X + y = 6

(C) x+2y + 6 = 0 (d) NONE of these

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The equation of the line through (4,1), whose x-interceptis double its y-intercept, is(a) x+2y=6(b) 2x + y = 6(c) x+2y + 6 = 0 (d) none of these​

(C) x+2y + 6 = 0 (d) NONE of these

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The equation of the line through (4,1), whose x-interceptis double its y-intercept, is(a) x+2y=6(b) 2x + y = 6(c) x+2y + 6 = 0 (d) none of these