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The equation of the line passing through the points of intersection of the circles `3x^2 +3y^2-2x + 12y-9=0 and x^2+y^2+6x+2y-15=0` is

Answer» Equation of straight line passing through intersection of two circles `C_(1) and C_(2)` is `(S_(1)-S_(2))=0`
`therefore x^(2)+y^(2)-(2)/(3)x+4y-3-(x^(2)+y^(2)+6x+2y-15)=0`
`rArr (20)/(3)x-2y-12=0 rArr10x-3y-18=0`


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