1.

The equation of the line joining the origin to the point (-4,5)

Answer»

\text{Concept used:}

\text{The equation of <klux>LINE</klux> joining two points $(x_1,y_1)$ and $(x_2,y_2)$}

\text{ is }\;\displaystyle\bf\frac{y-y_1}{y_2-y_1}=\frac{x-x_1}{x_2-x_1}

\text{Given points are (0,0) and (-4,5)}

\text{The equation of line joining two points (0,0) and (-4,5)}

\text{ is }\;\displaystyle\frac{y-y_1}{y_2-y_1}=\frac{x-x_1}{x_2-x_1}

\implies\displaystyle\frac{y-0}{5-0}=\frac{x-0}{-4-0}

\implies\displaystyle\frac{y}{5}=\frac{x}{-4}

\implies\;\displaystyle\;5x=-4y

\implies\;\displaystyle\;5x+4y=0

\therefore\textbf{The equation of the line joining origin to the point is 5x+4y=0 }

Find more:

Point A(7,-3) and B(1,9), find:

a. SLOPE of AB.

b. Equation of line PERPENDICULAR bisector of the line AB.

c. He value of 'p' of (-2,p) lies on it.

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