1.

The equation of the circle having centre (1, –2) and passing through the point of intersection of the lines 3x + y = 14 and 3x + 5y = 18 is(a) x2 + y2 – 2x + 4y – 20 = 0(b) x2 + y2 – 2x – 4y – 20 = 0(c) x2 + y2 + 2x – 4y – 20 = 0(d) x2 + y2 + 2x + 4y – 20 = 0

Answer» The equation of the circle having centre (1, –2) and passing through the point of intersection of the lines 3x + y = 14 and 3x + 5y = 18 is

(a) x2 + y2 – 2x + 4y – 20 = 0

(b) x2 + y2 – 2x – 4y – 20 = 0

(c) x2 + y2 + 2x – 4y – 20 = 0

(d) x2 + y2 + 2x + 4y – 20 = 0


Discussion

No Comment Found