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The equation of the circle having centre (1, –2) and passing through the point of intersection of the lines 3x + y = 14 and 3x + 5y = 18 is(a) x2 + y2 – 2x + 4y – 20 = 0(b) x2 + y2 – 2x – 4y – 20 = 0(c) x2 + y2 + 2x – 4y – 20 = 0(d) x2 + y2 + 2x + 4y – 20 = 0 |
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Answer» The equation of the circle having centre (1, –2) and passing through the point of intersection of the lines 3x + y = 14 and 3x + 5y = 18 is (a) x2 + y2 – 2x + 4y – 20 = 0 (b) x2 + y2 – 2x – 4y – 20 = 0 (c) x2 + y2 + 2x – 4y – 20 = 0 (d) x2 + y2 + 2x + 4y – 20 = 0 |
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