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The equation of perpendicular bisectors of the sidesAB and AC of a triangle ABC are x- y +5 = 0 and x + 2y =0 respectively. If the point A is (1,- 2), thenthe equation of line BC is

Answer» The equation of perpendicular bisectors of the sidesAB and AC of a triangle ABC are x- y +5 = 0 and x + 2y =0 respectively. If the point A is (1,- 2), thenthe equation of line BC is


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