the equation of line passing through (-1,3) and (4,-1)

1.	the equation of line passing through (-1,3) and (4,-1)
Answer» First find the gradient of the line using the formulay2−y1/x2−x1 =(-1) - 3/4 - (-1)= - 4/5 Next, use the equation of a line which is (y−y1) = m(x−x1), where m is the gradient (y − 3) = - 4/5(x − −1) y − 3 = - 4x/5 - 4/5 y = - 4x/5 - 4/5 + 3 y = - 4x/5 + 11/5 Therefore, Equation of line isy = - 4x/5 + 11/5

Answer»

First find the gradient of the line using the formulay2−y1/x2−x1

=(-1) - 3/4 - (-1)= - 4/5

Next, use the equation of a line which is

(y−y1) = m(x−x1), where m is the gradient

(y − 3) = - 4/5(x − −1)

y − 3 = - 4x/5 - 4/5

y = - 4x/5 - 4/5 + 3

y = - 4x/5 + 11/5

Therefore, Equation of line isy = - 4x/5 + 11/5

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