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The equation of alternating of alternating current for a cuicuit is given by `I = 50 cos 100 pi t`. Calculate (i) frequency of a.c. applied,(ii) virtual value of current, (iii) value of current `1//600` s after it was maximum |
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Answer» Here, `I = 50 cos 100 pi t` Compare it with the standard form `I = I_(0) cos omega t`, we get `I_(0) = 50 A` `omega = 2 pi, v = (100 pi)/(2 pi) = 50 c//s` Virtual value of current, `I_(v) = (1)/(sqrt2) = (50)/(sqrt2)` At `t = 0, I = 50 cos 0 = 50 A = max`. At `t = (1)/(600) s` `I = 50 cos 100 pi xx (1)/(600) = 50 "cos" (pi)/(6)` `= 50 cos 30^(@) = (50sqrt3)/(2) = 25sqrt3 A` |
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