The equation of a straight line is3x - 3y -7=0 find you intercept of t

1.	The equation of a straight line is3x - 3y -7=0 find you intercept of the line
Answer» e are two forms of equation of STRAIGHT LINE:- $\quad \quad \bullet \sf{y = mx + c}$ where m is the slope/gradient of the graph and c is the y intercept (the point where the graph CUTS the y axis). And, $\quad \quad \bullet \sf{\dfrac{x}{a} + \dfrac{y}{b} = 1}$ where a is the x intercept and b is the y intercept $\sf{\\ \\}$ We can solve this problem USING both these equations. $\sf{\\ \\}$ 1st method:- $\longrightarrow \sf{ 3x - 3y - 7 = 0}$ $\longrightarrow \sf{ 3y = 3x - 7 }$ $\longrightarrow \sf{ y = \dfrac{3x - 7}{3} }$ $\longrightarrow \sf{ y = x - \dfrac{7}{3} }$ $\longrightarrow \sf { y = 1x + \dfrac{-7}{3} }$ Comparing with $\sf{y = mx + c}$ , we can observe that, $\longrightarrow \sf{c = \dfrac{-7}{3} }$ And we know that c is the y intercept $\longrightarrow \underline{\underline{\sf{y\:intercept = \dfrac{-7}{3}}}}$ $\sf{\\ \\}$ 2nd method:- $\longrightarrow \sf{ 3x - 3y - 7 = 0}$ $\longrightarrow \sf{3x - 3y = 7}$ $\longrightarrow \sf{\dfrac{3x - 3y}{7} = 1}$ $\longrightarrow \sf{ \dfrac{3x}{7} - \dfrac{3y}{7} = 1}$ $\longrightarrow \sf{ \dfrac{x}{(\dfrac{7}{3})} - \dfrac{y}{(\dfrac{7}{3})} = 1}$ $\longrightarrow \sf{ \dfrac{x}{(\dfrac{7}{3})} + \dfrac{y}{(\dfrac{-7}{3})} = 1}$ Comparing with $\sf{\dfrac{x}{a} + \dfrac{y}{b} = 1}$ , we can observe that, $\longrightarrow \sf{b = \dfrac{-7}{3} }$ And we know that b is the y intercept $\longrightarrow \underline{\underline{\sf{y\:intercept = \dfrac{-7}{3}}}}$ $\sf{\\}$