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The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is(a) x2 + y2 = 9a2(b) x2 + y2 = 16a2(c) x2 + y2 = 4a2(d) x2 + y2 = a2 |
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Answer» The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is (a) x2 + y2 = 9a2 (b) x2 + y2 = 16a2 (c) x2 + y2 = 4a2 (d) x2 + y2 = a2 |
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