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The equation for the angular displacement of a particle moving along a circular path is given by Φ = 2t^3 + 0.5 where Φ is in radian and t is in seconds. the angular velocity of the particle at time t= 2 sec is​

Answer» ANGULAR DISPLACEMENT =2t^3+0.5Angular VELOCITY=6t^2+0At t=2sec...Angular velocity =6*2*2=24 radian per secondHope you are satisfied with the answer PLEASE MARK AS BRAINLIEST


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