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The entropy change for eaction at 300 K is 120 `Jk^(-1) mol^(-1)` . What is the enthalpy change for the reaction ? |
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Answer» Correct Answer - `Delta H^(@) = 36 kJ mol^(-1)` `Delta S^(@) = (Delta H^(@))/(T)` `:. Delta H^(@) = T Delta S^(@)` `= 300 xx 120` `= 3.6 xx 10^(4) Jmol^(-1)` ` =36 kJ mol^(-1)` |
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