1.

The entropy change for eaction at 300 K is 120 `Jk^(-1) mol^(-1)` . What is the enthalpy change for the reaction ?

Answer» Correct Answer - `Delta H^(@) = 36 kJ mol^(-1)`
`Delta S^(@) = (Delta H^(@))/(T)`
`:. Delta H^(@) = T Delta S^(@)`
`= 300 xx 120`
`= 3.6 xx 10^(4) Jmol^(-1)`
` =36 kJ mol^(-1)`


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