The enthalpy of neutralization of HCl and NaOH is −57 kJ mol−1. Th – InterviewSolution

1.	The enthalpy of neutralization of HCl and NaOH is −57 kJ mol−1. The heat evolved at constant pressure (in kJ) when 0.5 mole of H2SO4 react with 0.75 mole of NaOH is equal to
Answer» The enthalpy of neutralization of $H C l$ and $N a O H$ is $- 57 k J m o l^{- 1}$ . The heat evolved at constant pressure (in kJ) when $0.5 m o l e$ of H2SO4 react with $0.75 m o l e$ of $N a O H$ is equal to

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