1.

The enthalpy change for the transition of liquid water to steam is 41 kj/mol at 100°c and 1 atmpressure calculate entropy change for the process.

Answer»

Entropy change of vaporisation  

∆Sv  = ∆Hv /T  

∆Hv = 41 x 103 J , T= 373 K  

So Sv = (41 x 103)/373 = 109.92 JK-1mol-1



Discussion

No Comment Found

Related InterviewSolutions