Saved Bookmarks
| 1. |
The energy of the electron in the ground state of hydrogen is - 13.6 eV. Calculate the energy of the photon that would be emitted if the electron were to make a transition corresponding to the emission of the first line of the (i) Lyman series, (ii) Balmer series of the hydrogen spectrum. |
|
Answer» Solution :ENERGY of ELECTRON in ground state (n = 1) of hydrogen E, = - 13.6 eV. (i) Firstline of Lyman series is emitted fortransition n = 2 ton=1 . Hence . `E_(2) = (E_(1))/((2)^(2)) = - (13.6)/(9) = - 3.4 eV` `therefore ` ENERGYOF the emitted photon `E_(1)= E_(3) - E_(2) = - 1.51 -(-3.4) = 1.89 eV` |
|