1.

The energy of a photon corresponding to the maximum wavelength of visible light is?

Answer»
<klux>ENERGY</klux> =   \frac{hc}{ a}
where H is Planck's constant=6.626×10^-34 m/s. me and C is speed of light and a is MAXIMUM WAVELENGTH of visible light which is 8000A°. 8000A°=8×10^3×10^-10=8×10^-7 m. Energy=6.626×10^-34(3×10^8)/8×10^-7
=>Energy =19.878×10^-25/8×10^-7
=>Energy=2.48475×10^-18J.


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