1.

The energy equivalent of one atomic mass unit is

Answer»

Solution :`E=Delta mc^2 Deltam= 1.6605 xx 10^(-27)KG`
`=1.6605 xx 10^(-27)xx(3xx10^8)^2`
`=1.4924 xx 10^(-4)J`
`=(1.4924 xx 10^(-10))/(1.6 xx10^(-19))EV`
`= 0.9315 xx 10^9 eV`
= 931.5 MeV


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