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The energy change due to the reaction `2Na(s) +CI_(2) (g) rarr2Na CI(s)` is `-826kJ` The consumption of 1 mo1 of `CI_(2)` gas contracts the system by `22.4L` at 1 atm What is the enthalphy change of the reaction . |
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Answer» `W = P DeltaV = 1atm xx 22.4 L = 22.4 L atm` `= 22.4 L atm xx 101.3J` `= 2.27 xx 10^(3) = 2.27 kJ` The work done on the system is to be subtracted form the energy change to get enthalpy change, `DeltaH = DeltaU +P DeltaV` `=- 826 kJ + (-2.27 kJ) =- 828.27 kJ` |
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