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the enequal sides of an isosceles triangle measure 20cm and its area is 60 cm square and find its perimeter of the given triangle |
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Answer» let the height of triangle be hso Area of triangle = bh/260 = (20 × h)/23 = h/2h = 6 cm So Side of triangle ish² + (b/2)² = (side)²6² + 10² = (side)²136 = (side)²side = √(136) cm side = 2 √34 cm Perimeter of triangle = 2 √34 + 2 √34 + 20= (4√34 + 20) cm please check the answer thanks. wanna to be friends |
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