The ends of a stretched wire of length L are fixed at x=0 and x=L In o

1.	The ends of a stretched wire of length L are fixed at x=0 and x=L In one experiment, the displacement of the wire is y1=Asin (πxL)sin ωt and energy is E1, and in another experiment its displacement is y2=Asin(2πxL)sin 2ωt and energy is E2. Then
Answer» The ends of a stretched wire of length L are fixed at x=0 and x=L In one experiment, the displacement of the wire is $y_{1} = A s i n (\frac{π x}{L}) s i n ω t$ and energy is $E_{1}$ , and in another experiment its displacement is $y_{2} = A s i n (\frac{2 π x}{L}) s i n 2 ω t$ and energy is $E_{2}$ . Then

The ends of a stretched wire of length L are fixed at x=0 and x=L In one experiment, the displacement of the wire is y1=Asin (πxL)sin ωt and energy is E1, and in another experiment its displacement is y2=Asin(2πxL)sin 2ωt and energy is E2. Then

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The ends of a stretched wire of length L are fixed at x=0 and x=L In one experiment, the displacement of the wire is $y_{1} = A s i n (\frac{π x}{L}) s i n ω t$ and energy is $E_{1}$ , and in another experiment its displacement is $y_{2} = A s i n (\frac{2 π x}{L}) s i n 2 ω t$ and energy is $E_{2}$ . Then

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The ends of a stretched wire of length L are fixed at x=0 and x=L In one experiment, the displacement of the wire is y1=Asin (πxL)sin ωt and energy is E1, and in another experiment its displacement is y2=Asin(2πxL)sin 2ωt and energy is E2. Then

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