The ends of a quadrant of a circle have the coordinates (1, 3) and (3,1). Then the center of such a circle is(2, 2) (b) (1, 1)(c) (4, 4)(d) (2, 6)A. (2,2)B. (1,1)C. (4,4)D. (2,6)

The ends of a quadrant of a circle have the coordinates (1, 3) and (3,

1.	The ends of a quadrant of a circle have the coordinates (1, 3) and (3,1). Then the center of such a circle is(2, 2) (b) (1, 1)(c) (4, 4)(d) (2, 6)A. (2,2)B. (1,1)C. (4,4)D. (2,6)
Answer» Correct Answer - 2 If `(alpha,beta)` is the center, then `(alpha-1)^(2)+(beta-3)^(2)=(alpha-3)^(2)+(beta-1)^(2)` (1) and `(beta-3)/(alpha-1).(beta-1)/(alpha-3)= -1` or `(alpha-1)(alpha-3)+(beta-1)(beta-3)=0` (2) From (1), `4 alpha -4beta=0` `:. alpha =beta` From (2), `2(alpha-1)(alpha-3)=0` `:. alpha=1,3` `:. (alpha,beta)-=(1,1),(3,3)`

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The ends of a quadrant of a circle have the coordinates (1, 3) and (3,1). Then the center of such a circle is(2, 2) (b) (1, 1)(c) (4, 4)(d) (2, 6)A. (2,2)B. (1,1)C. (4,4)D. (2,6)

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