The end product of decay of ""_(90)Th^(232) is ""_(82)Pb^(208) . The n – InterviewSolution

1.	The end product of decay of ""_(90)Th^(232) is ""_(82)Pb^(208) . The number of alpha and beta particles emitted are respectively
Answer» SOLUTION :LETA and b be the NUMBER of `alpha beta` particlesemitted duringthe change comparingthe mass numbers 232 +208 +4a+b x0 4a=232-208 a=6 number of `alpha`paritcle emitted =6 NUMBEROF `beta` particles emitted =4

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