The emissive power per wavelength interval Eλ of a blackbody at an a

1.	The emissive power per wavelength interval Eλ of a blackbody at an absolute temperature T1 is maximum at λ1 = 1.1 µm. At an absolute temperature T2 , its R is maximum at λ2 = 0.55 µm. Then, \(\frac{T_1}{T_2}\) is equal to(A) \(\frac{1}2\)(B) 1 (C) 2 (D) 4.
Answer» Correct Option is (A) \(\frac{1}{2}\) Acoording to Wiens displacement law : \(\lambda T = b\) \(\lambda_1 T_1 = \lambda_2 T_2\) \(\frac{T_1}{T_2} = \frac{0.55}{1.10}\) \(\frac{T_1}{T_2} = \frac{1}{2}\) Correct option is (A) \(\frac{1}2\)

The emissive power per wavelength interval Eλ of a blackbody at an absolute temperature T1 is maximum at λ1 = 1.1 µm. At an absolute temperature T2 , its R is maximum at λ2 = 0.55 µm. Then, \(\frac{T_1}{T_2}\) is equal to(A) \(\frac{1}2\)(B) 1 (C) 2 (D) 4.

Answer»

Correct Option is (A) \(\frac{1}{2}\)

Acoording to Wiens displacement law :

\(\lambda T = b\)

\(\lambda_1 T_1 = \lambda_2 T_2\)

\(\frac{T_1}{T_2} = \frac{0.55}{1.10}\)

\(\frac{T_1}{T_2} = \frac{1}{2}\)

Correct option is (A) \(\frac{1}2\)