The emf of the cell with the cell reaction given below is 0.28 V at 25 – InterviewSolution

1.	The emf of the cell with the cell reaction given below is 0.28 V at 25oC.Zn(s) + 2H+(aq)→Zn2+(aq, 0.1 M) + H2(g, 1 atm Calculate the pH of the hydrogen electrodeGiven:E0Zn2+/Zn = −0.76 VE0H+/H2 = 0 V
Answer» The emf of the cell with the cell reaction given below is $0.28 V$ at $25^{o} C$ . $Z n (s) + 2 H^{+} (a q) \to Z n^{2 +} (a q, 0.1 M) + H_{2} (g, 1 a t m$ Calculate the $p H$ of the hydrogen electrode Given: $E_{Z n^{2 +} / Z n}^{0} = - 0.76 V$ $E_{H^{+} / H_{2}}^{0} = 0 V$

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