The emf of the cell reaction, Zn(s)+Cu2+(aq.)→Zn2+(aq.)+Cu(s) is 1.1 – InterviewSolution

1.	The emf of the cell reaction, Zn(s)+Cu2+(aq.)→Zn2+(aq.)+Cu(s) is 1.1V. If enthalpy of the reaction is −216.7kJmol−1, calculate the entropy change for the reaction(in J/Kmole)
Answer» The emf of the cell reaction, $Z n (s) + {C u}^{2 +} (a q .) \to {Z n}^{2 +} (a q .) + C u (s)$ is $1.1 V$ . If enthalpy of the reaction is $- 216.7 k J {m o l}^{- 1}$ , calculate the entropy change for the reaction(in J/Kmole)

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