The emf of the cell: Ni / Ni2+ (1.0 M) // Au3+ (1.0 M) / Au (E° = -0.25 V for Ni2+/Ni; E° = 1.5 V for Au3+/Au) is (a) 1.25 V (b) -1.25 V (c) 1.75 V (d) 2.0 V

The emf of the cell: Ni / Ni2+ (1.0 M) // Au3+ (1.0 M) / Au (E° = -

1.	The emf of the cell: Ni / Ni2+ (1.0 M) // Au3+ (1.0 M) / Au (E° = -0.25 V for Ni2+/Ni; E° = 1.5 V for Au3+/Au) is (a) 1.25 V (b) -1.25 V (c) 1.75 V (d) 2.0 V
Answer» OPTION (c) is the right ANSWER EXPLANATION:REFER attachments for explanation!!!