The EMF of the cell M|Mn+ (0.02 M)||H+ (1 M)|H2 (g)(1 atm),Pt at 25∘ – InterviewSolution

1.	The EMF of the cell M\|Mn+ (0.02 M)\|\|H+ (1 M)\|H2 (g)(1 atm),Pt at 25∘C is 0.81 V. Calculate the valency of the metal if the standard oxidation potential of the metal is 0.76 V.(Given, log4=0.6)
Answer» The EMF of the cell $M \| M^{n^{+}} (0.02 M) \| \| H^{+} (1 M) \| H_{2} (g) (1 atm), P t$ at $25^{\circ} C$ is $0.81 V$ . Calculate the valency of the metal if the standard oxidation potential of the metal is $0.76 V$ . (Given, $log 4 = 0.6$ )

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