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The emf of a Daniell cell at 298 K is E_(1) Zn|ZnSO_(4)(0.01 M)||CuSO_(4)(1.0M)|Cu When the concentration of ZNSO_(4) is 1.0 M and that of CuSO_(4) is 0.01 M, the emf changed to E_(2). What is the relationship between E_(1) and E_(2) ? |
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Answer» `E_1ltE_2` |
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