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The emf of a cell corresponding to the reaction Zn(s) + 2H+(aq)→Zn2+(0.1 M) + H2(g, 1 bar) is 0.28 V at 25∘ C. Calculate the pH of the solution at the hydrogen electrode. Given E∘Zn2+|Zn=−0.763 V

Answer»

The emf of a cell corresponding to the reaction Zn(s) + 2H+(aq)Zn2+(0.1 M) + H2(g, 1 bar) is 0.28 V at 25 C. Calculate the pH of the solution at the hydrogen electrode. Given EZn2+|Zn=0.763 V



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