1.

The elevator shown in figure (5−E5) is descending with an acceleration of 2 m/s2. The mass of the block A is 0.5 kg. What force is exerted by the block A on the block B?Figure

Answer»

Answer:

The force exerted by the block A on the block B is 4 N.

Explanation:

When the ELEVATOR is descending, a pseudo-force acts on it in the UPWARD direction.

From the free-body DIAGRAM of block A,

mg-N=ma

N=m(g-a)

⇒N=0.5(10-2)

=4 N

So, the force exerted by the block A on the block B is 4 N.



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