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The elevator shown in figure (5−E5) is descending with an acceleration of 2 m/s2. The mass of the block A is 0.5 kg. What force is exerted by the block A on the block B?Figure |
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Answer» Answer: The force exerted by the block A on the block B is 4 N. Explanation: When the ELEVATOR is descending, a pseudo-force acts on it in the UPWARD direction. From the free-body DIAGRAM of block A, mg-N=ma N=m(g-a) ⇒N=0.5(10-2) =4 N So, the force exerted by the block A on the block B is 4 N. |
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