The electrostatic pressure experienced by a small section of a charged conductor due to the remaining surface, in an electric field of intensity 6 V/m is x×10−12 Nm−2. Then, the value of x is [Take ϵ0=8.85×10−12 C2/Nm2]

The electrostatic pressure experienced by a small section of a charged

1.	The electrostatic pressure experienced by a small section of a charged conductor due to the remaining surface, in an electric field of intensity 6 V/m is x×10−12 Nm−2. Then, the value of x is [Take ϵ0=8.85×10−12 C2/Nm2]
Answer» The electrostatic pressure experienced by a small section of a charged conductor due to the remaining surface, in an electric field of intensity $6 V/m$ is $x \times 10^{- 12} {Nm}^{- 2}$ . Then, the value of $x$ is [Take $ϵ_{0} = 8.85 \times 10^{- 12} C^{2} {/Nm}^{2}$ ]

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The electrostatic pressure experienced by a small section of a charged conductor due to the remaining surface, in an electric field of intensity 6 V/m is x×10−12 Nm−2. Then, the value of x is [Take ϵ0=8.85×10−12 C2/Nm2]

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