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The electrostatic potential existing in the space is given as `V=-((x^(3))/(6epsilon_(0))+2)` volts. Find the charge density (in `"coulomb"//m^(3)`) at `x=2m`. |
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Answer» Correct Answer - 2 `E=-(delV)/(delx)-(3x^(2))/(6epsilon_(0))=(x^(2))/(2epsilon_(0))` `phi=E.A. =(x^(2))/(2epsilon_(0))A` `(dphi)/(dx)=((xA))/(epsilon_(0))impliesdphi=((xAdx))/(epsilon_(0))` `rho(x)=(dq)/(Adx)=((xAdx))/((Adx))=x` `rho(x=2)=2` Alternating Method `gradvecE=(rho)/(epsilon_(0))impliesx/(epsilon_(0))=(rho)/(epsilon_(0))impliesrho=x` If `x=2impliesrho=2` |
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