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the electrostatic force of repulsion between two positively charged ions carrying equal charge is 7.4×10^-9N, when they are separated by a distance of 5×10^-10m . What is the value of charge ? How many electrons are missing from each ion? |
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Answer» Number of missing ELECTRON from each ion is 3Explanation : GIVEN : The ELECTROSTATIC forve of repulsion between two positively charged ions CARRYING equal charge is 7.4× 10⁻⁹ N Distance of separation , d = 5× 10⁻¹⁰m = 5A⁰ We have to find the number of electron mission from each ions Let US suppose charges is q₁ = q₂ = q (given equal charges) Let n be the number of electron missing Using columb's law F = kq²/r² q²= F× r² /k q²= 7.4 × 10⁻⁹ × (5× 10⁻¹⁰) ²/9× 10⁹ q²= 7.4×25× 10⁻²⁹/9×10⁹ q² = 20.56 × 10⁻³⁸ /9q = √20.56 ×10³⁸ ≈ 4.5×10⁻¹⁹ C as q = ne so, n = q/e = 4.5×10⁻¹⁹/1.6×10⁻¹⁹ [∵Charge of electrone is 1.6×10⁻⁹C]n = 2.81 roundly n = 3 Since, Number of electron missing from each ion is 3 . |
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