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The electronic configuration of M3+ is [ Kr ] 4d10 . Its position in the periodic table is |
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Answer» 5th period GROUP number 13 EXPLANATION:M3+ is [Kr] 4d10 Therefore, M = [Kr] 4d10 5s2 5p1 Here the OUTERMOST electron enters into the N−shell i.e n=5 hence the it belongs to 5th period.The outermost electron enters into the P orbital hence it belongs to p block.For p-block elements no. of group = (12+no of electrons in p orbital) = 12+1 = 13 Hope it helps! Best wishes! |
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