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The electric force experienced by a charge of 1*10^-6c is 1.5*10^-3n.Find the magnitude of the electric field at the position of the charge |
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Answer» orce, F=1.5*10^-3 NCharge, q=1*10^-6 CForce = charge x ELECTRIC fieldF=qEE=F/qE=(1.5*10^-3)/(1*10^-6)E=1500 N/Chence, the electric FIELD at position of charge is 1500 N/C |
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