the electric field of a light wave is given by E = Eo[i sin (wt-kz). + j sin (wt-kz-π/4)] the polarisation state of the wave is

the electric field of a light wave is given by E = Eo[i sin (wt-kz). +

1.	the electric field of a light wave is given by E = Eo[i sin (wt-kz). + j sin (wt-kz-π/4)] the polarisation state of the wave is
Answer» The electric field of an electromagnetic wave in free space is given byE→ =10cos(10 7 t+kx) j^ V/m, where t and x are in seconds and metres RESPECTIVELY. It can be inferred that(i) the wavelength λ is 188.4 m.(ii) the wave number k is 0.33 rad/m.(III) the wave amplitude is 10 V/m.(iv) the wave is propagating along +x direction.Which one of the following pairs of statements is correct?MEDIUMHelp best friendStudy laterVIDEO EXPLANATIONANSWERAs given: E= 10cos(10 7 t+kx)COMPARING it with standard equation of e.m. wave,E= E 0 cos(ωt+kx)Amplitude, E 0 =10 V/m and ω=10 7 rad/s∵C=vλ= 2πωλ or λ= ω2πc = 10 7 2π×3×10 8 =188.4 MALSO,c= kω or k= cω = 3×10 8 10 7 = 0.033The wave is propagating along y direction.How satisfied are you with the answer?This will help us to improve betterMore Questions by difficultyEASYMEDIUMHARD

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the electric field of a light wave is given by E = Eo[i sin (wt-kz). + j sin (wt-kz-π/4)] the polarisation state of the wave is​

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the electric field of a light wave is given by E = Eo[i sin (wt-kz). + j sin (wt-kz-π/4)] the polarisation state of the wave is